What is the solution for 9y^{''}+30y^'+25y=0 ?

The solution for 9y^{''}+30y^'+25y=0 is y=c_{1}e^{-(5t)/3}+c_{2}e^{-(5t)/3}t

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9y^{''}+30y^'+25y=0

9 y^{^{''}} + 30 y^{^{'}} + 25 y = 0

y = c_{1} e^{- \frac{5 t}{3}} + c_{2} e^{- \frac{5 t}{3}} t

Solution steps

9 y^{''} (t) + 30 y^{'} (t) + 25 y = 0

Solve linear ODE:

y = c_{1} e^{- \frac{5 t}{3}} + c_{2} e^{- \frac{5 t}{3}} t

y = c_{1} e^{- \frac{5 t}{3}} + c_{2} e^{- \frac{5 t}{3}} t

\int 6 x sec^{2} (2 x) d x

n = 0 \sum \infty 3 - 7 (0.6)^{n}

\int \frac{1}{1 + e ^{z}} d z

x + y^{2} = 6, x + y = 0

What is the solution for 9y^{''}+30y^'+25y=0 ?
The solution for 9y^{''}+30y^'+25y=0 is y=c_{1}e^{-(5t)/3}+c_{2}e^{-(5t)/3}t