What is the sum from n=0 to infinity of 3-7(0.6)^n ?

The sum from n=0 to infinity of 3-7(0.6)^n is diverges

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sum from n=0 to infinity of 3-7(0.6)^n

n = 0 \sum \infty 3 - 7 (0.6)^{n}

diverges

Solution steps

n = 0 \sum \infty 3 - 7 \cdot 0. 6^{n}

Apply Series Divergence Test:

diverges

= diverges

\int \frac{1}{1 + e ^{z}} d z

x + y^{2} = 6, x + y = 0

y = (x^{6} - 7 x + 4) (x^{4} - 5 x)

f (x) = x^{2} + 4

What is the sum from n=0 to infinity of 3-7(0.6)^n ?
The sum from n=0 to infinity of 3-7(0.6)^n is diverges