What is the integral of-4/25 x+58 ?

The integral of-4/25 x+58 is -(2x^2)/(25)+58x+C

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integral of-4/25 x+58

\int - \frac{4}{25} x + 58 d x

- \frac{2 x ^{2}}{25} + 58 x + C

Solution steps

\int - \frac{4}{25} x + 58 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int \frac{4}{25} x d x + \int 58 d x

\int \frac{4}{25} x d x = \frac{2 x ^{2}}{25}

\int 58 d x = 58 x

= - \frac{2 x ^{2}}{25} + 58 x

Add a constant to the solution

= - \frac{2 x ^{2}}{25} + 58 x + C

\int (\frac{2 x - 5}{7}) d x

\int (sec^{2} (x) - 9) d x

\int_{0}^{2} \frac{3 x ^{2} - 1}{x ^{2}} d x

y = 2 x^{3} - x^{2} + 7

\frac{\partial}{\partial x} (\frac{t}{a ^{2} t ^{2} - x ^{2}})

What is the integral of-4/25 x+58 ?
The integral of-4/25 x+58 is -(2x^2)/(25)+58x+C