What is (\partial)/(\partial x)(cos(x+9y)) ?

The answer to (\partial)/(\partial x)(cos(x+9y)) is -sin(x+9y)

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(\partial)/(\partial x)(cos(x+9y))

\frac{\partial}{\partial x} (cos (x + 9 y))

- sin (x + 9 y)

Solution steps

\frac{\partial}{\partial x} (cos (x + 9 y))

Treat

y

as a constant

Apply the chain rule:

- sin (x + 9 y) \frac{\partial}{\partial x} (x + 9 y)

= - sin (x + 9 y) \frac{\partial}{\partial x} (x + 9 y)

\frac{\partial}{\partial x} (x + 9 y) = 1

= - sin (x + 9 y) \cdot 1

Simplify

= - sin (x + 9 y)

y d y = x d x

\frac{d}{d y} (9 - y^{2})

\frac{d}{d x} (2^{x} + 2 cos (\frac{2 x}{2}))

\int 7 x^{3} x^{4} + 6 d x

(- 9, - 3), (7, - 7)

What is (\partial)/(\partial x)(cos(x+9y)) ?
The answer to (\partial)/(\partial x)(cos(x+9y)) is -sin(x+9y)