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Popular >

ty^'=t+y

Solution

t y^{^{'}} = t + y

Solution

y = ln (t) t + c_{1} t

Solution steps

t y^{'} (t) = t + y

Solve linear ODE:

y = ln (t) t + c_{1} t

y = ln (t) t + c_{1} t

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Frequently Asked Questions (FAQ)

What is the solution for ty^'=t+y ?
The solution for ty^'=t+y is y=ln(t)t+c_{1}t