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Popular >

integral from 0 to 3 of (x^3-x)

Solution

\int_{0}^{3} (x^{3} - x) d x

Solution

\frac{63}{4}

+1

Decimal Notation

15.75

Solution steps

\int_{0}^{3} x^{3} - x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{3} x^{3} d x - \int_{0}^{3} x d x

\int_{0}^{3} x^{3} d x = \frac{81}{4}

\int_{0}^{3} x d x = \frac{9}{2}

= \frac{81}{4} - \frac{9}{2}

Simplify

\frac{81}{4} - \frac{9}{2} : \frac{63}{4}

= \frac{63}{4}

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Frequently Asked Questions (FAQ)

What is the integral from 0 to 3 of (x^3-x) ?
The integral from 0 to 3 of (x^3-x) is 63/4