What is (\partial)/(\partial x)(x^3y^3+y-z+3) ?

The answer to (\partial)/(\partial x)(x^3y^3+y-z+3) is 3x^2y^3

Popular >

(\partial)/(\partial x)(x^3y^3+y-z+3)

\frac{\partial}{\partial x} (x^{3} y^{3} + y - z + 3)

3 x^{2} y^{3}

Solution steps

\frac{\partial}{\partial x} (x^{3} y^{3} + y - z + 3)

Treat

y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{3} y^{3}) + \frac{\partial}{\partial x} (y) - \frac{\partial}{\partial x} (z) + \frac{\partial}{\partial x} (3)

\frac{\partial}{\partial x} (x^{3} y^{3}) = 3 y^{3} x^{2}

\frac{\partial}{\partial x} (y) = 0

\frac{\partial}{\partial x} (z) = 0

\frac{\partial}{\partial x} (3) = 0

= 3 y^{3} x^{2} + 0 - 0 + 0

Simplify

= 3 x^{2} y^{3}

\frac{\partial}{\partial x} (x^{7} y^{8} - x^{6} y^{7})

e^{- 2 t} sin (3 t)

\int x csc^{2} (x) d x

x \to + (- 2) lim (\frac{- 9}{x ^{2}})

2 \leq x \leq 6, y = 2

What is (\partial)/(\partial x)(x^3y^3+y-z+3) ?
The answer to (\partial)/(\partial x)(x^3y^3+y-z+3) is 3x^2y^3