What is laplacetransform e^{-2t}sin(3t) ?

The answer to laplacetransform e^{-2t}sin(3t) is 3/((s+2)^2+9)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

laplacetransform e^{-2t}sin(3t)

laplace transform

e^{- 2 t} sin (3 t)

\frac{3}{( s + 2 ) ^{2} + 9}

Solution steps

L {e^{- 2 t} sin (3 t)}

Apply transform rule:

L {f (t)} = F (s)

then

L {e^{a t} f (t)} = F (s - a)

For

e^{- 2 t} sin (3 t) : f (t) = sin (3 t), a = - 2

= L {sin (3 t)} (s + 2)

L {sin (3 t)} : \frac{3}{s ^{2} + 9}

= \frac{3}{( s + 2 ) ^{2} + 9}

\int x csc^{2} (x) d x

x \to + (- 2) lim (\frac{- 9}{x ^{2}})

2 \leq x \leq 6, y = 2

x^{4} cos (7 x - 5)

2 a y

What is laplacetransform e^{-2t}sin(3t) ?
The answer to laplacetransform e^{-2t}sin(3t) is 3/((s+2)^2+9)