What is the integral of θsec(θ)tan(θ) ?

The integral of θsec(θ)tan(θ) is θsec(θ)-ln|tan(θ)+sec(θ)|+C

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integral of θsec(θ)tan(θ)

\int θ sec (θ) tan (θ) d θ

θ sec (θ) - ln ∣ tan (θ) + sec (θ) ∣ + C

Solution steps

\int θ sec (θ) tan (θ) d θ

Apply Integration By Parts

: θ sec (θ) - \int sec (θ) d θ

= θ sec (θ) - \int sec (θ) d θ

\int sec (θ) d θ = ln ∣ tan (θ) + sec (θ) ∣

= θ sec (θ) - ln ∣ tan (θ) + sec (θ) ∣

Add a constant to the solution

= θ sec (θ) - ln ∣ tan (θ) + sec (θ) ∣ + C

(\frac{f ( x ) + x - 6}{4 - 2 x})^{'}

\int (9 - x^{2}) d x

\frac{d}{d x} (16 ln (x^{2}) - x^{2})

\int \frac{x ^{3}}{x ^{2} + 64} d x

2^{x}

What is the integral of θsec(θ)tan(θ) ?
The integral of θsec(θ)tan(θ) is θsec(θ)-ln|tan(θ)+sec(θ)|+C