What is the solution for y^'sin(2pix)=piycos(2pix) ?

The solution for y^'sin(2pix)=piycos(2pix) is y=c_{1}sqrt(sin(2pix))

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y^'sin(2pix)=piycos(2pix)

y^{^{'}} sin (2 π x) = π y cos (2 π x)

y = c_{1} sin (2 π x)

Solution steps

y^{'} (x) sin (2 π x) = π y cos (2 π x)

Solve separable ODE:

y = c_{1} sin (2 π x)

y = c_{1} sin (2 π x)

x \to 1 - lim (4 - x - x^{2})

\frac{4}{s ^{3}}

\int x sin (7 - x) d x

\frac{d x}{d t} = x^{2} - 3

\int x^{3} 144 - x^{2} d x

What is the solution for y^'sin(2pix)=piycos(2pix) ?
The solution for y^'sin(2pix)=piycos(2pix) is y=c_{1}sqrt(sin(2pix))