What is inverse oflaplace 4/(s^3) ?

The answer to inverse oflaplace 4/(s^3) is 2t^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse oflaplace 4/(s^3)

inverse laplace

\frac{4}{s ^{3}}

2 t^{2}

Solution steps

L^{- 1} {\frac{4}{s ^{3}}}

= L^{- 1} {2 \cdot \frac{2}{s ^{3}}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= 2 L^{- 1} {\frac{2}{s ^{3}}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{( n ) !}{s ^{n + 1}}} = t^{n}

L^{- 1} {\frac{2}{s ^{3}}} = t^{2}

= 2 t^{2}

\int x sin (7 - x) d x

\frac{d x}{d t} = x^{2} - 3

\int x^{3} 144 - x^{2} d x

\frac{d}{d x} (- 3 x^{2} + 6 x)

x e^{3 x} (2 + 3 x)

What is inverse oflaplace 4/(s^3) ?
The answer to inverse oflaplace 4/(s^3) is 2t^2