What is the integral from 0 to 1 of (e^{x^2}) ?

The integral from 0 to 1 of (e^{x^2}) is (sqrt(pi))/2 \erfi(1)

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integral from 0 to 1 of (e^{x^2})

\int_{0}^{1} (e^{x^{2}}) d x

\frac{π}{2} erfi (1)

Solution steps

\int_{0}^{1} e^{x^{2}} d x

Use the nonelementary integral:

\int e^{x^{2}} d x = \frac{π}{2} erfi (x)

= [\frac{π}{2} erfi (x)]_{0}^{1}

Compute the boundaries:

\frac{π}{2} erfi (1)

= \frac{π}{2} erfi (1)

\frac{x}{y} \frac{d y}{d x} + ln (y) = x + 1

\int \frac{3}{4} x^{4} d x

x \to 2 + lim (\frac{2 x + 1}{x - 2})

cos (x^{5})

n = 0 \sum \infty (\frac{π}{e})^{n}

What is the integral from 0 to 1 of (e^{x^2}) ?
The integral from 0 to 1 of (e^{x^2}) is (sqrt(pi))/2 \erfi(1)