What is the derivative of 1200sqrt(x^2-0.1x) ?

The derivative of 1200sqrt(x^2-0.1x) is (600(2x-0.1))/(sqrt(x^2-0.1x))

What is the first derivative of 1200sqrt(x^2-0.1x) ?

The first derivative of 1200sqrt(x^2-0.1x) is (600(2x-0.1))/(sqrt(x^2-0.1x))

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\frac{d}{d x} (1200 x^{2} - 0.1 x)

\frac{600 ( 2 x - 0.1 )}{x ^{2} - 0.1 x}

Solution steps

\frac{d}{d x} (1200 x^{2} - 0.1 x)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 1200 \frac{d}{d x} (x^{2} - 0.1 x)

Apply the chain rule:

\frac{1}{2 x ^{2} - 0.1 x} \frac{d}{d x} (x^{2} - 0.1 x)

= \frac{1}{2 x ^{2} - 0.1 x} \frac{d}{d x} (x^{2} - 0.1 x)

\frac{d}{d x} (x^{2} - 0.1 x) = 2 x - 0.1

= 1200 \cdot \frac{1}{2 x ^{2} - 0.1 x} (2 x - 0.1)

Simplify

1200 \cdot \frac{1}{2 x ^{2} - 0.1 x} (2 x - 0.1) : \frac{600 ( 2 x - 0.1 )}{x ^{2} - 0.1 x}

= \frac{600 ( 2 x - 0.1 )}{x ^{2} - 0.1 x}

\frac{d}{d x} (\frac{1}{x ^{3} + 1})

\frac{d y}{d x} = x y + 4 x + 5 y + 20

\int \frac{( x - 2 ) ( x + 2 )}{x ^{2}} d x

\int_{0}^{2} \frac{3}{16 - x ^{2}} d x

\frac{d}{d x} ((cos (x))^{\frac{π}{5}})

What is the derivative of 1200sqrt(x^2-0.1x) ?
The derivative of 1200sqrt(x^2-0.1x) is (600(2x-0.1))/(sqrt(x^2-0.1x))
What is the first derivative of 1200sqrt(x^2-0.1x) ?
The first derivative of 1200sqrt(x^2-0.1x) is (600(2x-0.1))/(sqrt(x^2-0.1x))