What is the derivative of y=(16)/x ?

The derivative of y=(16)/x is -(16)/(x^2)

What is the first derivative of y=(16)/x ?

The first derivative of y=(16)/x is -(16)/(x^2)

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derivative of

y = \frac{16}{x}

- \frac{16}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{16}{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 16 \frac{d}{d x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 16 \frac{d}{d x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 16 (- 1 \cdot x^{- 1 - 1})

Simplify

16 (- 1 \cdot x^{- 1 - 1}) : - \frac{16}{x ^{2}}

= - \frac{16}{x ^{2}}

(7^{x})^{4}

y (θ) = e tan (θ)

\frac{d y}{d x} - 3 y = - 6

\int_{- \infty}^{0} 7^{x} d x

What is the derivative of y=(16)/x ?
The derivative of y=(16)/x is -(16)/(x^2)
What is the first derivative of y=(16)/x ?
The first derivative of y=(16)/x is -(16)/(x^2)