What is the derivative of y^{-2} ?

The derivative of y^{-2} is -2/(y^3)

What is the first derivative of y^{-2} ?

The first derivative of y^{-2} is -2/(y^3)

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derivative of

y^{- 2}

- \frac{2}{y ^{3}}

Solution steps

\frac{d}{d y} (y^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 2 y^{- 2 - 1}

Simplify

- 2 y^{- 2 - 1} : - \frac{2}{y ^{3}}

= - \frac{2}{y ^{3}}

x \to 1 lim (x - \frac{1}{ln ∣ x ∣})

6 x^{2} y^{^{'}} = y^{^{'}} + 8 x e^{- y}

\int \frac{4 x ^{2} + 4 x - 4}{x ^{3} + x ^{2} - x - 1} d x

\frac{\partial}{\partial y} (2 x z^{3} e^{y^{2}})

What is the derivative of y^{-2} ?
The derivative of y^{-2} is -2/(y^3)
What is the first derivative of y^{-2} ?
The first derivative of y^{-2} is -2/(y^3)