What is the derivative of 1/(16x^4) ?

The derivative of 1/(16x^4) is -1/(4x^5)

What is the first derivative of 1/(16x^4) ?

The first derivative of 1/(16x^4) is -1/(4x^5)

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\frac{d}{d x} (\frac{1}{16 x ^{4}})

- \frac{1}{4 x ^{5}}

Solution steps

\frac{d}{d x} (\frac{1}{16 x ^{4}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{16} \frac{d}{d x} (\frac{1}{x ^{4}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{1}{16} \frac{d}{d x} (x^{- 4})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{16} (- 4 x^{- 4 - 1})

Simplify

\frac{1}{16} (- 4 x^{- 4 - 1}) : - \frac{1}{4 x ^{5}}

= - \frac{1}{4 x ^{5}}

- 3 y^{^{'}} + \frac{3 y}{x} = x y^{4}

\int \frac{x}{( x ^{2} - 3 ) ^{3}} d x

\int (4 sin (5 x) + 5 cos (3 x)) d x

- cos (x^{2}) sin (x) + e^{- x - 2}

\frac{\partial}{\partial x} (e^{2 x + 5 y})

What is the derivative of 1/(16x^4) ?
The derivative of 1/(16x^4) is -1/(4x^5)
What is the first derivative of 1/(16x^4) ?
The first derivative of 1/(16x^4) is -1/(4x^5)