What is the derivative of-cos(x^2)sin(x)+e^{-x-2} ?

The derivative of-cos(x^2)sin(x)+e^{-x-2} is 2xsin(x^2)sin(x)-cos(x)cos(x^2)-e^{-x-2}

What is the first derivative of-cos(x^2)sin(x)+e^{-x-2} ?

The first derivative of-cos(x^2)sin(x)+e^{-x-2} is 2xsin(x^2)sin(x)-cos(x)cos(x^2)-e^{-x-2}

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derivative of

- cos (x^{2}) sin (x) + e^{- x - 2}

2 x sin (x^{2}) sin (x) - cos (x) cos (x^{2}) - e^{- x - 2}

Solution steps

\frac{d}{d x} (- cos (x^{2}) sin (x) + e^{- x - 2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (cos (x^{2}) sin (x)) + \frac{d}{d x} (e^{- x - 2})

\frac{d}{d x} (cos (x^{2}) sin (x)) = - 2 x sin (x^{2}) sin (x) + cos (x) cos (x^{2})

\frac{d}{d x} (e^{- x - 2}) = - e^{- x - 2}

= - (- 2 x sin (x^{2}) sin (x) + cos (x) cos (x^{2})) - e^{- x - 2}

Simplify

= 2 x sin (x^{2}) sin (x) - cos (x) cos (x^{2}) - e^{- x - 2}

\frac{\partial}{\partial x} (e^{2 x + 5 y})

\frac{d}{d x} (cos (x - \frac{π}{4}))

y = 4 x^{2} - 2 x + (- 9)

\frac{d}{d u} (uv)

\int 7 x^{\frac{3}{4}} d x

What is the derivative of-cos(x^2)sin(x)+e^{-x-2} ?
The derivative of-cos(x^2)sin(x)+e^{-x-2} is 2xsin(x^2)sin(x)-cos(x)cos(x^2)-e^{-x-2}
What is the first derivative of-cos(x^2)sin(x)+e^{-x-2} ?
The first derivative of-cos(x^2)sin(x)+e^{-x-2} is 2xsin(x^2)sin(x)-cos(x)cos(x^2)-e^{-x-2}