What is the solution for 4y^{''}-12y^'+9y=0 ?

The solution for 4y^{''}-12y^'+9y=0 is y=c_{1}e^{(3t)/2}+c_{2}e^{(3t)/2}t

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4y^{''}-12y^'+9y=0

4 y^{^{''}} - 12 y^{^{'}} + 9 y = 0

y = c_{1} e^{\frac{3 t}{2}} + c_{2} e^{\frac{3 t}{2}} t

Solution steps

4 y^{''} (t) - 12 y^{'} (t) + 9 y = 0

Solve linear ODE:

y = c_{1} e^{\frac{3 t}{2}} + c_{2} e^{\frac{3 t}{2}} t

y = c_{1} e^{\frac{3 t}{2}} + c_{2} e^{\frac{3 t}{2}} t

\int e^{\frac{t}{RC}} d t

\int 9 x^{7} d x

n = 2 \sum \infty \frac{( - 1 ^{n} )}{n}

f (x) = (x^{2} 6^{x})^{9}

What is the solution for 4y^{''}-12y^'+9y=0 ?
The solution for 4y^{''}-12y^'+9y=0 is y=c_{1}e^{(3t)/2}+c_{2}e^{(3t)/2}t