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Popular >

xy^'=2x^2+y,y(1)=3

Solution

x y^{^{'}} = 2 x^{2} + y, y (1) = 3

Solution

y = 2 x^{2} + x

Solution steps

x y^{'} (x) = 2 x^{2} + y

Solve linear ODE:

y = 2 x^{2} + x

y = 2 x^{2} + x

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\int \frac{4}{( x + 2 ) ^{2}} d x

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\int 3 x cos (8 x) d x

sum from n=1 to infinity of 5cos(2/n)

n = 1 \sum \infty 5 cos (\frac{2}{n})

Frequently Asked Questions (FAQ)

What is the solution for xy^'=2x^2+y,y(1)=3 ?
The solution for xy^'=2x^2+y,y(1)=3 is y=2x^2+x