What is the solution for (dy)/(dt)=2(y^2-y)t ?

The solution for (dy)/(dt)=2(y^2-y)t is y= 1/(1-e^{t^2+c_{1)}}

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(dy)/(dt)=2(y^2-y)t

\frac{d y}{d t} = 2 (y^{2} - y) t

y = \frac{1}{1 - e ^{t^{2} + c_{1}}}

Solution steps

\frac{d y}{d t} = 2 (y^{2} - y) t

Solve separable ODE:

y = \frac{1}{1 - e ^{t^{2} + c_{1}}}

y = \frac{1}{1 - e ^{t^{2} + c_{1}}}

\int 5 x + 4 d x

y = x^{4} - 3 x^{2} + 10, at x = 1

x \cdot y^{^{'}} = y + 2

\int (y^{2} + 4 y)^{2} d y

5 x^{3} + 2

What is the solution for (dy)/(dt)=2(y^2-y)t ?
The solution for (dy)/(dt)=2(y^2-y)t is y= 1/(1-e^{t^2+c_{1)}}