What is (x+1)^2(x^2+1)^{-3} ?

The solution to (x+1)^2(x^2+1)^{-3} is ((x+1)^2)/((x^2+1)^3)

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simplify (x+1)^2(x^2+1)^{-3}

simplify

(x + 1)^{2} (x^{2} + 1)^{- 3}

\frac{( x + 1 ) ^{2}}{( x ^{2} + 1 ) ^{3}}

Solution steps

(x + 1)^{2} (x^{2} + 1)^{- 3}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(x^{2} + 1)^{- 3} = \frac{1}{( x ^{2} + 1 ) ^{3}}

= (x + 1)^{2} \frac{1}{( x ^{2} + 1 ) ^{3}}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( x + 1 ) ^{2} \cdot 1}{( x ^{2} + 1 ) ^{3}}

Apply rule:

a \cdot 1 = a

(x + 1)^{2} \cdot 1 = (x + 1)^{2}

= \frac{( x + 1 ) ^{2}}{( x ^{2} + 1 ) ^{3}}

\frac{d y}{d x} - \frac{y}{x} = - \frac{5}{2} x^{2} y^{3}

4 (t - 2) e^{4 t}

y^{^{'}} + \frac{y}{x} = \frac{1}{x}

\frac{\partial}{\partial x} (ln (2 + sin (x y)))

\frac{\partial}{\partial z} (z x^{2})

What is (x+1)^2(x^2+1)^{-3} ?
The solution to (x+1)^2(x^2+1)^{-3} is ((x+1)^2)/((x^2+1)^3)