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Popular >

area y=(x+1)^2,(-1,0)

Solution

area

y = (x + 1)^{2}, (- 1, 0)

Solution

\frac{1}{3}

+1

Decimal Notation

0.33333 \dots

Solution steps

Apply the area formula:

\int_{- 1}^{0} ∣ x + 1 ∣^{2} d x

Solve

\int_{- 1}^{0} ∣ x + 1 ∣^{2} d x : \frac{1}{3}

The area is:

= \frac{1}{3}

Popular Examples

integral of ke^{-2x}

\int k e^{- 2 x} d x

derivative of y=(x-1)/(x+1)derivative of

y = \frac{x - 1}{x + 1}

limit as x approaches 0-of arccos(e^{-x^2})

x \to 0 - lim (arccos (e^{- x^{2}}))

tangent of (x+2)^2+(y-3)^2=37,(-3,-3)tangent of

(x + 2)^{2} + (y - 3)^{2} = 37, (- 3, - 3)

integral from 0 to pi/4 of 3cos^5(2x)

\int_{0}^{\frac{π}{4}} 3 cos^{5} (2 x) d x

Frequently Asked Questions (FAQ)

What is area y=(x+1)^2,(-1,0) ?
The answer to area y=(x+1)^2,(-1,0) is 1/3