What is (\partial)/(\partial y)(x-1/y) ?

The answer to (\partial)/(\partial y)(x-1/y) is 1/(y^2)

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(\partial)/(\partial y)(x-1/y)

\frac{\partial}{\partial y} (x - \frac{1}{y})

\frac{1}{y ^{2}}

Solution steps

\frac{\partial}{\partial y} (x - \frac{1}{y})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x) - \frac{\partial}{\partial y} (\frac{1}{y})

\frac{\partial}{\partial y} (x) = 0

\frac{\partial}{\partial y} (\frac{1}{y}) = - \frac{1}{y ^{2}}

= 0 - (- \frac{1}{y ^{2}})

Simplify

= \frac{1}{y ^{2}}

(- 1.2) (4.3)

y^{^{'}} = - 2 t y^{2}

\int_{0}^{\infty} \frac{1}{3 + x} d x

n = 1 \sum \infty \frac{9}{( - 2 ) ^{n}}

x \to 1 - lim (e^{\frac{1}{x - 1}})

What is (\partial)/(\partial y)(x-1/y) ?
The answer to (\partial)/(\partial y)(x-1/y) is 1/(y^2)