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Popular >

y^'=-2ty^2

Solution

y^{^{'}} = - 2 t y^{2}

Solution

y = - \frac{1}{- t ^{2} + c _{1}}

Solution steps

y^{'} (t) = - 2 t y^{2}

Solve separable ODE:

y = - \frac{1}{- t ^{2} + c _{1}}

y = - \frac{1}{- t ^{2} + c _{1}}

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Frequently Asked Questions (FAQ)

What is the solution for y^'=-2ty^2 ?
The solution for y^'=-2ty^2 is y=-1/(-t^2+c_{1)}