What is the tangent of f(x)=18sqrt(x),(9,54) ?

The tangent of f(x)=18sqrt(x),(9,54) is y=3x+27

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tangent of f(x)=18sqrt(x),(9,54)

tangent of

f (x) = 18 x, (9, 54)

y = 3 x + 27

Solution steps

Find the slope of

f (x) = 18 x : \frac{df ( x )}{d x} = \frac{9}{x}

Compute the slope of

f (x) = 18 x

(9, 54) : m = 3

Find the line with slope m=

3

and passing through

(9, 54) : y = 3 x + 27

y = 3 x + 27

\frac{d}{d x} ((2 x + 5)^{3})

y^{^{'}} = x e^{x + y}

\frac{d}{d x} (x^{3} - 3 x^{2} - 9 x + 4)

s^{- \frac{3}{2}}

\int x^{2} - 1 d x

What is the tangent of f(x)=18sqrt(x),(9,54) ?
The tangent of f(x)=18sqrt(x),(9,54) is y=3x+27