What is area e^x,e^{-x},[-2,1] ?

The answer to area e^x,e^{-x},[-2,1] is e^2+(1+e^3+e)/(e^2)-4

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area e^x,e^{-x},[-2,1]

area

e^{x}, e^{- x}, [- 2, 1]

e^{2} + \frac{1 + e ^{3} + e}{e ^{2}} - 4

Decimal Notation

6.61055 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{1} e^{x} - e^{- x} d x

Solve

\int_{- 2}^{1} e^{x} - e^{- x} d x : e^{2} + \frac{1 + e ^{3} + e}{e ^{2}} - 4

The area is:

= e^{2} + \frac{1 + e ^{3} + e}{e ^{2}} - 4

\frac{d}{d x} (\frac{2 ( 1 + x ^{2} )}{( 1 - x ^{2} ) ^{2}})

\frac{\partial}{\partial x} (y^{6} cos (6 x))

\int z sin (8 z) d z

\frac{\partial}{\partial x} (x e^{x} cos (y))

\frac{d}{d x} (arcsin (5 x + 1))

What is area e^x,e^{-x},[-2,1] ?
The answer to area e^x,e^{-x},[-2,1] is e^2+(1+e^3+e)/(e^2)-4