What is the derivative of f(x)=x^2+5 ?

The derivative of f(x)=x^2+5 is 2x

What is the first derivative of f(x)=x^2+5 ?

The first derivative of f(x)=x^2+5 is 2x

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derivative of

f (x) = x^{2} + 5

2 x

Solution steps

\frac{d}{d x} (x^{2} + 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (5)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (5) = 0

= 2 x + 0

Simplify

= 2 x

\frac{d}{d x} (cos (2 x + π))

\int \frac{1}{( 1 - x ) ^{3}} d x

(9 - 2 x^{3})^{3}

\frac{d}{d x} (x^{r})

\frac{d}{d x} (e^{x^{2} - y^{2}} sin (2 x y))

What is the derivative of f(x)=x^2+5 ?
The derivative of f(x)=x^2+5 is 2x
What is the first derivative of f(x)=x^2+5 ?
The first derivative of f(x)=x^2+5 is 2x