What is the derivative of (x-5/(4x^2e^x)) ?

The derivative of (x-5/(4x^2e^x)) is (-x^2+4x+10)/(4e^xx^3)

What is the first derivative of (x-5/(4x^2e^x)) ?

The first derivative of (x-5/(4x^2e^x)) is (-x^2+4x+10)/(4e^xx^3)

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Popular >

\frac{d}{d x} (\frac{x - 5}{4 x ^{2} e ^{x}})

\frac{- x ^{2} + 4 x + 10}{4 e ^{x} x ^{3}}

Solution steps

\frac{d}{d x} (\frac{x - 5}{4 x ^{2} e ^{x}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{4} \frac{d}{d x} (\frac{x - 5}{x ^{2} e ^{x}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{1}{4} \cdot \frac{\frac{d}{d x} ( x - 5 ) x ^{2} e ^{x} - \frac{d}{d x} ( x ^{2} e ^{x} ) ( x - 5 )}{( x ^{2} e ^{x} ) ^{2}}

\frac{d}{d x} (x - 5) = 1

\frac{d}{d x} (x^{2} e^{x}) = 2 x e^{x} + e^{x} x^{2}

= \frac{1}{4} \cdot \frac{1 \cdot x ^{2} e ^{x} - ( 2 x e ^{x} + e ^{x} x ^{2} ) ( x - 5 )}{( x ^{2} e ^{x} ) ^{2}}

Simplify

\frac{1}{4} \cdot \frac{1 \cdot x ^{2} e ^{x} - ( 2 x e ^{x} + e ^{x} x ^{2} ) ( x - 5 )}{( x ^{2} e ^{x} ) ^{2}} : \frac{- x ^{2} + 4 x + 10}{4 e ^{x} x ^{3}}

= \frac{- x ^{2} + 4 x + 10}{4 e ^{x} x ^{3}}

x \to 0 lim (x^{4} cos (\frac{1}{x}))

(e^{- 2 t})^{^{'}}

\int \frac{- 6 x ^{4} + 6}{x ^{2} + 1} d x

\int \frac{1}{e ^{10 x}} d x

\frac{d}{d x} (x^{3} - 3 x^{2} - 2 x + 1)

What is the derivative of (x-5/(4x^2e^x)) ?
The derivative of (x-5/(4x^2e^x)) is (-x^2+4x+10)/(4e^xx^3)
What is the first derivative of (x-5/(4x^2e^x)) ?
The first derivative of (x-5/(4x^2e^x)) is (-x^2+4x+10)/(4e^xx^3)