What is the tangent of f(x)=4sin(x),(pi/6 ,2) ?

The tangent of f(x)=4sin(x),(pi/6 ,2) is y=2sqrt(3)x+2-pi/(sqrt(3))

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tangent of f(x)=4sin(x),(pi/6 ,2)

tangent of

f (x) = 4 sin (x), (\frac{π}{6}, 2)

y = 23 x + 2 - \frac{π}{3}

Solution steps

Find the slope of

f (x) = 4 sin (x) : \frac{df ( x )}{d x} = 4 cos (x)

Compute the slope of

f (x) = 4 sin (x)

(\frac{π}{6}, 2) : m = 23

Find the line with slope m=

23

and passing through

(\frac{π}{6}, 2) : y = 23 x + 2 - \frac{π}{3}

y = 23 x + 2 - \frac{π}{3}

\frac{d}{d x} (tanh (x^{2} - 9))

x \to 7 lim (x^{4})

\int (6 x - 5) (3 x^{2} - 5 x)^{3} d x

\int y^{\frac{3}{2}} d y

ln (cos (t))

What is the tangent of f(x)=4sin(x),(pi/6 ,2) ?
The tangent of f(x)=4sin(x),(pi/6 ,2) is y=2sqrt(3)x+2-pi/(sqrt(3))