What is the tangent of y=6e^xcos(x),(0,6) ?

The tangent of y=6e^xcos(x),(0,6) is y=6x+6

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tangent of y=6e^xcos(x),(0,6)

tangent of

y = 6 e^{x} cos (x), (0, 6)

y = 6 x + 6

Solution steps

Find the slope of

y = 6 e^{x} cos (x) : \frac{d y}{d x} = 6 (e^{x} cos (x) - e^{x} sin (x))

Compute the slope of

y = 6 e^{x} cos (x)

(0, 6) : m = 6

Find the line with slope m=

6

and passing through

(0, 6) : y = 6 x + 6

y = 6 x + 6

n = 1 \sum \infty π^{- n}

\frac{d ^{2}}{d x ^{2}} y = x^{3}

\frac{d}{d x} (3 ln (x^{2}))

\frac{\partial}{\partial x} (e^{2 y} - y cos (x y))

y = e^{x}, y = e^{- 3 x}, x = ln (3)

What is the tangent of y=6e^xcos(x),(0,6) ?
The tangent of y=6e^xcos(x),(0,6) is y=6x+6