What is the derivative of 4x^{-2x} ?

The derivative of 4x^{-2x} is 4x^{-2x}(-2ln(x)-2)

What is the first derivative of 4x^{-2x} ?

The first derivative of 4x^{-2x} is 4x^{-2x}(-2ln(x)-2)

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\frac{d}{d x} (4 x^{- 2 x})

4 x^{- 2 x} (- 2 ln (x) - 2)

Solution steps

\frac{d}{d x} (4 x^{- 2 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (x^{- 2 x})

Apply exponent rule:

a^{b} = e^{b l n (a)}

x^{- 2 x} = e^{(- 2 x) l n (x)}

= 4 \frac{d}{d x} (e^{(- 2 x) l n (x)})

Apply the chain rule:

e^{(- 2 x) l n (x)} \frac{d}{d x} ((- 2 x) ln (x))

= e^{(- 2 x) l n (x)} \frac{d}{d x} ((- 2 x) ln (x))

\frac{d}{d x} ((- 2 x) ln (x)) = - 2 ln (x) - 2

= 4 e^{(- 2 x) l n (x)} (- 2 ln (x) - 2)

Simplify

4 e^{(- 2 x) l n (x)} (- 2 ln (x) - 2) : 4 x^{- 2 x} (- 2 ln (x) - 2)

= 4 x^{- 2 x} (- 2 ln (x) - 2)

\frac{d y}{d x} = 1 - x y

\int \frac{1}{x ( 100 - x )} d x

\frac{d}{d x} (1 + x + x^{2})

\frac{( s + 6 )}{s ^{2} + 6 s + 25}

0.001 x^{3} + 4 x + 1458

What is the derivative of 4x^{-2x} ?
The derivative of 4x^{-2x} is 4x^{-2x}(-2ln(x)-2)
What is the first derivative of 4x^{-2x} ?
The first derivative of 4x^{-2x} is 4x^{-2x}(-2ln(x)-2)