What is the integral of 8x^2ln(x) ?

The integral of 8x^2ln(x) is 8(1/3 x^3ln(x)-(x^3)/9)+C

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integral of 8x^2ln(x)

\int 8 x^{2} ln (x) d x

8 (\frac{1}{3} x^{3} ln (x) - \frac{x ^{3}}{9}) + C

Solution steps

\int 8 x^{2} ln (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 8 \cdot \int x^{2} ln (x) d x

Apply Integration By Parts

: \frac{1}{3} x^{3} ln (x) - \int \frac{x ^{2}}{3} d x

= 8 (\frac{1}{3} x^{3} ln (x) - \int \frac{x ^{2}}{3} d x)

\int \frac{x ^{2}}{3} d x = \frac{x ^{3}}{9}

= 8 (\frac{1}{3} x^{3} ln (x) - \frac{x ^{3}}{9})

Add a constant to the solution

= 8 (\frac{1}{3} x^{3} ln (x) - \frac{x ^{3}}{9}) + C

\frac{\partial}{\partial x} (2 x^{2} y + 9 x y^{3})

\frac{d}{d t} (sin (t) + cos (t))

\frac{d y}{d x} + 3 y = 5

\frac{\partial}{\partial x} (\frac{1}{y - 3 x})

y = x^{3}, (- 1, 2)

What is the integral of 8x^2ln(x) ?
The integral of 8x^2ln(x) is 8(1/3 x^3ln(x)-(x^3)/9)+C