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Popular >

y^'+1/t y=0

Solution

y^{^{'}} + \frac{1}{t} y = 0

Solution

y = \frac{c _{1}}{t}

Solution steps

y^{'} (t) + \frac{1}{t} y = 0

Solve separable ODE:

y = \frac{c _{1}}{t}

y = \frac{c _{1}}{t}

Popular Examples

sum from n=1 to infinity of (x/n)^n

n = 1 \sum \infty (\frac{x}{n})^{n}

tangent of y=x^3-x,(1,0)tangent of

y = x^{3} - x, (1, 0)

derivative of x/(x^2-15)

\frac{d}{d x} (\frac{x}{x ^{2} - 15})

integral of 9/((x-2)(x^2+4))

\int \frac{9}{( x - 2 ) ( x ^{2} + 4 )} d x

slope of (4.4)(5.9)slope

(4.4) (5.9)

Frequently Asked Questions (FAQ)

What is the solution for y^'+1/t y=0 ?
The solution for y^'+1/t y=0 is y=(c_{1})/t