What is laplacetransform 2e^{t/2} ?

The answer to laplacetransform 2e^{t/2} is 4/(2s-1)

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laplacetransform 2e^{t/2}

laplace transform

2 e^{\frac{t}{2}}

\frac{4}{2 s - 1}

Solution steps

L {2 e^{\frac{t}{2}}}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 2 L {e^{\frac{1}{2} t}}

L {e^{\frac{1}{2} t}} : \frac{2}{2 s - 1}

= 2 \cdot \frac{2}{2 s - 1}

Refine

2 \frac{2}{2 s - 1} : \frac{4}{2 s - 1}

= \frac{4}{2 s - 1}

\int_{0}^{1} y 1 - y^{2} d y

y = arctan (1) - x^{1} + x

\int_{2}^{t} \frac{1}{( 5 x ^{5} )} d x

\int \frac{tan ^{3} ( ln ( x ) )}{6 x} d x

\int \frac{1}{P - P ^{2}} d P

What is laplacetransform 2e^{t/2} ?
The answer to laplacetransform 2e^{t/2} is 4/(2s-1)