What is the tangent of y=x^2+8,(4,24) ?

The tangent of y=x^2+8,(4,24) is y=8x-8

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tangent of y=x^2+8,(4,24)

tangent of

y = x^{2} + 8, (4, 24)

y = 8 x - 8

Solution steps

Find the slope of

y = x^{2} + 8 : \frac{d y}{d x} = 2 x

Compute the slope of

y = x^{2} + 8

(4, 24) : m = 8

Find the line with slope m=

8

and passing through

(4, 24) : y = 8 x - 8

y = 8 x - 8

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