What is the limit as x approaches 0 of ln(x-1) ?

The limit as x approaches 0 of ln(x-1) is Does not exist

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limit as x approaches 0 of ln(x-1)

x \to 0 lim (ln (x - 1))

Does not exist

Solution steps

x \to 0 lim (ln (x - 1))

x \to a - lim f (x) = x \to a + lim f (x) = L

then

x \to a lim f (x) = L

x \to 0 - lim (ln (x - 1)) =

Does not exist

x \to 0 + lim (ln (x - 1)) =

Does not exist

= Does not exist

x \frac{d y}{d x} + 2 y = \frac{sin ( x )}{x}

\int cos (\frac{x}{7}) d x

2 y^{^{''}} + 3 y^{^{'}} - 2 y = 2 x - 3

y^{^{''}} - 8 y^{^{'}} + 16 y = t^{- 4} e^{4 t}

\int_{1}^{2} 5 x^{2} ln (x) d x

What is the limit as x approaches 0 of ln(x-1) ?
The limit as x approaches 0 of ln(x-1) is Does not exist