What is the derivative of x^2+3x+2 ?

The derivative of x^2+3x+2 is 2x+3

What is the first derivative of x^2+3x+2 ?

The first derivative of x^2+3x+2 is 2x+3

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\frac{d}{d x} (x^{2} + 3 x + 2)

2 x + 3

Solution steps

\frac{d}{d x} (x^{2} + 3 x + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (3 x) + \frac{d}{d x} (2)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (2) = 0

= 2 x + 3 + 0

Simplify

= 2 x + 3

6 \cdot 6^{t} + 2 \cdot 2 t

\int \frac{sin ( 3 x )}{csc ^{2} ( 4 x )} d x

\frac{d y}{d x} = \frac{1 - y}{1 - x}

\frac{\partial}{\partial v} (2 v sin (u))

\frac{1}{s ^{2} - s}

What is the derivative of x^2+3x+2 ?
The derivative of x^2+3x+2 is 2x+3
What is the first derivative of x^2+3x+2 ?
The first derivative of x^2+3x+2 is 2x+3