What is the integral from 1 to infinity of xe^{-14x} ?

The integral from 1 to infinity of xe^{-14x} is (15)/(196e^{14)}

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integral from 1 to infinity of xe^{-14x}

\int_{1}^{\infty} x e^{- 14 x} d x

\frac{15}{196 e ^{14}}

Decimal Notation

6.36374 E - 8

Solution steps

\int_{1}^{\infty} x e^{- 14 x} d x

Compute the indefinite integral:

\int x e^{- 14 x} d x = \frac{1}{196} (- 14 e^{- 14 x} x - e^{- 14 x}) + C

Compute the boundaries:

\int_{1}^{\infty} x e^{- 14 x} d x = 0 - (- \frac{15}{196 e ^{14}})

= 0 - (- \frac{15}{196 e ^{14}})

Simplify

= \frac{15}{196 e ^{14}}

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What is the integral from 1 to infinity of xe^{-14x} ?
The integral from 1 to infinity of xe^{-14x} is (15)/(196e^{14)}