What is the integral of xcos(10x) ?

The integral of xcos(10x) is 1/100 (10xsin(10x)+cos(10x))+C

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integral of xcos(10x)

\int x cos (10 x) d x

\frac{1}{100} (10 x sin (10 x) + cos (10 x)) + C

Solution steps

\int x cos (10 x) d x

Apply u-substitution

: \int \frac{u cos ( u )}{100} d u

= \int \frac{u cos ( u )}{100} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{100} \cdot \int u cos (u) d u

Apply Integration By Parts

: u sin (u) - \int sin (u) d u

= \frac{1}{100} (u sin (u) - \int sin (u) d u)

\int sin (u) d u = - cos (u)

= \frac{1}{100} (u sin (u) - (- cos (u)))

Substitute back

u = 10 x

= \frac{1}{100} (10 x sin (10 x) - (- cos (10 x)))

Simplify

= \frac{1}{100} (10 x sin (10 x) + cos (10 x))

Add a constant to the solution

= \frac{1}{100} (10 x sin (10 x) + cos (10 x)) + C

\frac{d}{d x} (arcsec (\frac{1}{x}))

\int_{- 1}^{1} (1 - x) d x

\int \frac{x - 1}{x ^{2} + 9} d x

y^{^{''}} + 4 y^{^{'}} + 5 y = 8

- 5 x^{2} + 4

What is the integral of xcos(10x) ?
The integral of xcos(10x) is 1/100 (10xsin(10x)+cos(10x))+C