What is (\partial)/(\partial x)(3x^2+2y^2) ?

The answer to (\partial)/(\partial x)(3x^2+2y^2) is 6x

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(\partial)/(\partial x)(3x^2+2y^2)

\frac{\partial}{\partial x} (3 x^{2} + 2 y^{2})

6 x

Solution steps

\frac{\partial}{\partial x} (3 x^{2} + 2 y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 x^{2}) + \frac{\partial}{\partial x} (2 y^{2})

\frac{\partial}{\partial x} (3 x^{2}) = 6 x

\frac{\partial}{\partial x} (2 y^{2}) = 0

= 6 x + 0

Simplify

= 6 x

\int_{z - 1}^{1} 3 x^{2} - 4 z x + 2 z^{2}

\frac{d}{d x} (ln (3 x^{2} + 4))

x \to - 5 lim (\frac{x ^{2} - 8}{5 - x})

\frac{d}{d x} (24 x^{\frac{3}{2}})

\frac{d y}{d x} = 5 x (x - 3)

What is (\partial)/(\partial x)(3x^2+2y^2) ?
The answer to (\partial)/(\partial x)(3x^2+2y^2) is 6x