What is the derivative of y=x^{-9} ?

The derivative of y=x^{-9} is -9/(x^{10)}

What is the first derivative of y=x^{-9} ?

The first derivative of y=x^{-9} is -9/(x^{10)}

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derivative of

y = x^{- 9}

- \frac{9}{x ^{10}}

Solution steps

\frac{d}{d x} (x^{- 9})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 9 x^{- 9 - 1}

Simplify

- 9 x^{- 9 - 1} : - \frac{9}{x ^{10}}

= - \frac{9}{x ^{10}}

\frac{d}{d x} (10 sin^{3} (x))

\frac{\partial}{\partial x} (y^{3} cos (3 x))

e^{3 x} + 1, y = 0, x = 0, x = 0.6

y^{^{''}} + 14 y^{^{'}} + 49 y = 0, y (0) = 0, y^{^{'}} (0) = 1

\frac{\partial}{\partial x} ((2 x + 2 y)^{\frac{1}{2}})

What is the derivative of y=x^{-9} ?
The derivative of y=x^{-9} is -9/(x^{10)}
What is the first derivative of y=x^{-9} ?
The first derivative of y=x^{-9} is -9/(x^{10)}