What is the d/(dt)(tan(3t)) ?

The d/(dt)(tan(3t)) is sec^2(3t)*3

What is the first d/(dt)(tan(3t)) ?

The first d/(dt)(tan(3t)) is sec^2(3t)*3

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\frac{d}{d t} (tan (3 t))

sec^{2} (3 t) \cdot 3

Solution steps

\frac{d}{d t} (tan (3 t))

Apply the chain rule:

sec^{2} (3 t) \frac{d}{d t} (3 t)

= sec^{2} (3 t) \frac{d}{d t} (3 t)

\frac{d}{d t} (3 t) = 3

= sec^{2} (3 t) \cdot 3

\frac{\partial}{\partial x} (\frac{3 x ^{2}}{5 - x})

\int \frac{1}{( 1 + 9 x ^{2} )} d x

9 \cdot t + 1

\frac{d}{d x} (x e^{- \frac{x}{4}})

\frac{d}{d x} (\frac{y}{y - x})