What is area-x^3+x,x=-1,y=-1/2 ?

The answer to area-x^3+x,x=-1,y=-1/2 is 1.05171…

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area-x^3+x,x=-1,y=-1/2

area

- x^{3} + x, x = - 1, y = - \frac{1}{2}

1.05171 \dots

Solution steps

Apply the area formula:

\int_{- 1}^{1.19148 \dots} \frac{1}{2} - x^{3} + x d x

Solve

\int_{- 1}^{1.19148 \dots} \frac{1}{2} - x^{3} + x d x : 1.05171 \dots

The area is:

= 1.05171 \dots

\int \frac{5 x + 1}{x ^{2} + 4 x + 5} d x

\int_{0}^{5} \frac{2}{x ^{2}} d x

\frac{d y}{d t} = - \frac{y}{t} - 7

\frac{d}{d x} (\frac{2}{( 1 - x ) ^{3}})

\frac{\partial}{\partial x} (z \cdot lo g_{e} (x^{2} + y^{2}))

What is area-x^3+x,x=-1,y=-1/2 ?
The answer to area-x^3+x,x=-1,y=-1/2 is 1.05171…