What is the derivative of 6pir^2 ?

The derivative of 6pir^2 is 12pir

What is the first derivative of 6pir^2 ?

The first derivative of 6pir^2 is 12pir

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derivative of

6 π r^{2}

12 π r

Solution steps

\frac{d}{d r} (6 π r^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 π \frac{d}{d r} (r^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 6 π 2 r^{2 - 1}

Simplify

= 12 π r

\int \frac{1}{( x ^{2} + 2 )} d x

\int \frac{- 3 x ^{3} + 2 x ^{2} - 28 x + 10}{x ^{2} + 9} d x

\frac{d}{d x} (y^{2} - x)

\int x^{4} (x^{5} - 5)^{3} d x

f (x) = lo g_{e} (x)

What is the derivative of 6pir^2 ?
The derivative of 6pir^2 is 12pir
What is the first derivative of 6pir^2 ?
The first derivative of 6pir^2 is 12pir