What is the derivative of y^2-x ?

The derivative of y^2-x is 2y(dy)/(dx)-1

What is the first derivative of y^2-x ?

The first derivative of y^2-x is 2y(dy)/(dx)-1

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\frac{d}{d x} (y^{2} - x)

2 y \frac{d y}{d x} - 1

Solution steps

\frac{d}{d x} (y^{2} - x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (y^{2}) - \frac{d x}{d x}

\frac{d}{d x} (y^{2}) = 2 y \frac{d y}{d x}

\frac{d x}{d x} = 1

= 2 y \frac{d y}{d x} - 1

\int x^{4} (x^{5} - 5)^{3} d x

f (x) = lo g_{e} (x)

\int \frac{x ^{2}}{x ^{2} - 1} d x

\frac{\partial}{\partial x} (x^{\frac{2}{3}} y^{\frac{1}{3}})

\frac{d}{d x} ((1 + x^{2})^{2})

What is the derivative of y^2-x ?
The derivative of y^2-x is 2y(dy)/(dx)-1
What is the first derivative of y^2-x ?
The first derivative of y^2-x is 2y(dy)/(dx)-1