What is the derivative of (1+x^2^2) ?

The derivative of (1+x^2^2) is 4x(1+x^2)

What is the first derivative of (1+x^2^2) ?

The first derivative of (1+x^2^2) is 4x(1+x^2)

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\frac{d}{d x} ((1 + x^{2})^{2})

4 x (1 + x^{2})

Solution steps

\frac{d}{d x} ((1 + x^{2})^{2})

Apply the chain rule:

2 (1 + x^{2}) \frac{d}{d x} (1 + x^{2})

= 2 (1 + x^{2}) \frac{d}{d x} (1 + x^{2})

\frac{d}{d x} (1 + x^{2}) = 2 x

= 2 (1 + x^{2}) \cdot 2 x

Simplify

= 4 x (1 + x^{2})

\frac{d}{d x} ((2 x^{4} - 6 x^{2} + 5)^{2})

- y + y^{^{'}} - y = e^{x} cos (x)

\frac{d ^{2} y}{d x ^{2}}, x y + 7 ey (x) = 7 e

f (x) = tan (x) - 1 sec (x)

What is the derivative of (1+x^2^2) ?
The derivative of (1+x^2^2) is 4x(1+x^2)
What is the first derivative of (1+x^2^2) ?
The first derivative of (1+x^2^2) is 4x(1+x^2)