What is the derivative of (2x+4^2) ?

The derivative of (2x+4^2) is 4(2x+4)

What is the first derivative of (2x+4^2) ?

The first derivative of (2x+4^2) is 4(2x+4)

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\frac{d}{d x} ((2 x + 4)^{2})

4 (2 x + 4)

Solution steps

\frac{d}{d x} ((2 x + 4)^{2})

Apply the chain rule:

2 (2 x + 4) \frac{d}{d x} (2 x + 4)

= 2 (2 x + 4) \frac{d}{d x} (2 x + 4)

\frac{d}{d x} (2 x + 4) = 2

= 2 (2 x + 4) \cdot 2

Simplify

= 4 (2 x + 4)

\int \frac{3 x ^{2} - 2 x - 9}{x ^{3} - x ^{2} - 9 x + 9} d x

\int \frac{x}{( x ^{2} + y ^{2} + z ^{2} ) ^{\frac{3}{2}}} d x

(- 8.8) (- 4.3)

\int e^{5 x} sin (x) d x

x y^{^{'}} = y + 2 x^{2} sin (x)

What is the derivative of (2x+4^2) ?
The derivative of (2x+4^2) is 4(2x+4)
What is the first derivative of (2x+4^2) ?
The first derivative of (2x+4^2) is 4(2x+4)