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Popular >

xy^'=y+2x^2sin(x)

Solution

x y^{^{'}} = y + 2 x^{2} sin (x)

Solution

y = - 2 cos (x) x + c_{1} x

Solution steps

x y^{'} (x) = y + 2 x^{2} sin (x)

Solve linear ODE:

y = - 2 cos (x) x + c_{1} x

y = - 2 cos (x) x + c_{1} x

Popular Examples

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\int_{1}^{2} x^{3} (x^{2} - 4) d x

inverse oflaplace (10)/(s(s+50))inverse laplace

\frac{10}{s ( s + 50 )}

area y=2sqrt(x),y=x area

y = 2 x, y = x

(\partial)/(\partial x)(sin(4x^2))

\frac{\partial}{\partial x} (sin (4 x^{2}))

Frequently Asked Questions (FAQ)

What is the solution for xy^'=y+2x^2sin(x) ?
The solution for xy^'=y+2x^2sin(x) is y=-2cos(x)x+c_{1}x