What is (\partial)/(\partial x)(sin(4x^2)) ?

The answer to (\partial)/(\partial x)(sin(4x^2)) is cos(4x^2)*8x

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(\partial)/(\partial x)(sin(4x^2))

\frac{\partial}{\partial x} (sin (4 x^{2}))

cos (4 x^{2}) \cdot 8 x

Solution steps

\frac{\partial}{\partial x} (sin (4 x^{2}))

Apply the chain rule:

cos (4 x^{2}) \frac{\partial}{\partial x} (4 x^{2})

= cos (4 x^{2}) \frac{\partial}{\partial x} (4 x^{2})

\frac{\partial}{\partial x} (4 x^{2}) = 8 x

= cos (4 x^{2}) \cdot 8 x

\int - 3 x e^{x} d x

\int \frac{3}{x} + x d x

\int_{0}^{27} \frac{5}{x ^{\frac{2}{3}}} d x

y^{^{'}} = 3 x + y, y (0) = 2

\int x^{2} + 5 d x

What is (\partial)/(\partial x)(sin(4x^2)) ?
The answer to (\partial)/(\partial x)(sin(4x^2)) is cos(4x^2)*8x