What is the integral from 0 to 27 of 5/(x^{2/3)} ?

The integral from 0 to 27 of 5/(x^{2/3)} is 45

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integral from 0 to 27 of 5/(x^{2/3)}

\int_{0}^{27} \frac{5}{x ^{\frac{2}{3}}} d x

45

Solution steps

\int_{0}^{27} \frac{5}{x ^{\frac{2}{3}}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot \int_{0}^{27} \frac{1}{x ^{\frac{2}{3}}} d x

Apply the Power Rule

: [3 x^{\frac{1}{3}}]_{0}^{27}

= 5 [3 x^{\frac{1}{3}}]_{0}^{27}

Compute the boundaries:

9

= 5 \cdot 9

Simplify

= 45

y^{^{'}} = 3 x + y, y (0) = 2

\int x^{2} + 5 d x

r \to 0 lim (sin^{2} (r))

(2 - 3 x^{3})^{- 2}

\frac{e ^{- 5 s}}{( s - 2 ) ^{4}}

What is the integral from 0 to 27 of 5/(x^{2/3)} ?
The integral from 0 to 27 of 5/(x^{2/3)} is 45